#include <stdio.h>
#include <math.h>


int main()
{
    int i8, i5, i3, i2, i1, n8, n5, n3, n2, n1;
    float max = 0, term;
    for(i8 = 0; i8 < 3; i8++)
        for(i5 = 0; i5 <= (20 - 8 * i8)/5; i5++)
            for(i3 = 0; i3 <= (20 - 8 * i8 - 5 * i5)/3; i3++)
                for(i2 = 0; i2 <= (20 - 8 * i8 - 5 * i5 - 3 * i3)/2; i2++){
                    i1 = 20 - 8 * i8 - 5 * i5 - 3 * i3 - 2 * i2;
                    term = 2000.0 * pow((double)(1 + 0.0063 * 12),(double)i1)
                                  * pow((double)(1 + 2 * 0.0066 * 12),(double)i2)
                                  * pow((double)(1 + 3 * 0.0069 * 12),(double)i3)
                                  * pow((double)(1 + 5 * 0.0075 * 12),(double)i5)
                                  * pow((double)(1 + 8 * 0.0084 * 12),(double)i8);
                    if(term > max)
                    {
                        max = term; n1 = i1; n2 = i2; n3 = i3; n5 = i5; n8 = i8;
                    }
                }
    printf("for maxinum profit, he should so save his money in a bank:\n");
    printf(" made fixed deposit for 8 year: %d times\n", n8);
    printf(" made fixed deposit for 5 year: %d times\n", n5);
    printf(" made fixed deposit for 3 year: %d times\n", n3);
    printf(" made fixed deposit for 2 year: %d times\n", n2);
    printf(" made fixed deposit for 1 year: %d times\n", n1);
    printf("           Total: %.2f\n", max);

    return 0;
}
//熊贤豪